Question

show that
${6}^{n}$
cannot end with the digit 0 for any natural number n.


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Answer 1

Step-by-step explanation:

6n can end with 0, the must have 2 and 5 as it prime factors . since it has no 5 as its prime factor

Answer 2

Answer:

If any digit has the last digit 10 that means it divisible by 10.

The factor of 10=2×5,

So value of 6ⁿ should be divisible by 2 and 5.

Both 6ⁿ is divisible by 2 but not divisible by 5.

So, it can not end with 0.