Question

Show that, $\log \frac{a^{2}}{bc} + \log \frac{b^{2}}{ca} + \log \frac{c^{2}}{ab} = 0$

Answer 1

Answer:

0

Step-by-step explanation:

Concept:

1.Product rule of logarithm:

$log_a(MNP)=log_aM+log_aN+log_aP$

2. Logarithm of 1 to any base is 0

That is, $log_a1=0$

$log\frac{a^2}{bc}+log\frac{b^2}{ca}+log\frac{c^2}{ca}\\\\= log(\frac{a^2b^2c^2}{(ab)(bc)(ca)})\\\\= log(\frac{a^2b^2c^2}{a^2b^2c^2})$

= log 1

= 0