Question

show that the accerlation due to gravity at the surface of the moon is about one-third sixth ​

Answer 1

Answer:

The escape velocity of an object is given by the equation v

e

=

R

2GM

.

where G is the gravitational constant, M is the mass of the planet, and R is the distance you're at from the centre of the planet.

In this case, the acceleration due to gravity on the surface of the moon is one sixth that on the surface of earth's and the diameter of the moon is one fourth of that of earth.

Therefore, the escape velocity in the moon will be v

e

=

4

1

R

2

6

1

GM

=

24

1

R

2GM

.

Hence, the ratio of escape velocity on moon and earth will be

24

1

.

Answer 2

Answer:

Consider an object of mass m at a height h from the surface of the Earth. We find that g'< g . This means that as altitude h increases the acceleration due to gravity g decreases.