Question

show that the angle of an equilateral triangle are 60°each.

Answer 1

Heya mate,

$we \: know \: that \: in \: equilateral \: triangle \\ All \: angles \: are \: equal. \\ and \: also \\ Sum \: of \: all \: angles \: of \: a \: triangle \: = 180 \\ let \: all \: angles \: be \: x \: . \\ so \\ x + x + x = 180 \\ 3x = 180 \\ x = 60 \\ hence \: proved.$
hope it will help you

#Kevin

Answer 2

Hello mate ^_^

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Solution:

∆ABC is equilateral which means that

AB=BC=AC.

AB=AC means that ∠B=∠C                  (In triangle, angles opposite to equal sides are equal)  .....(1)

AB=BC means that ∠A=∠C         (In triangle, angles opposite to equal sides are equal) ...... (2)

From (1) and (2), we can say that

∠A=∠B=∠C                                     .........(3)

Also, ∠A+∠B+∠C=180°             (Angle sum property of triangle)

Putting (3) in the above equation, we get

∠A+∠A+∠A=180°

⇒3∠A=180°

⇒∠A=180/3=60°                .......(4)

From (3) and (4), we can say that

∠A=∠B=∠C=60°

hope, this will help you.

Thank you______❤

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