show that the angle of an equilateral tringalare 60 degree each
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triangle A B C = 180 degrees
angle AB + Angle BC + Angle AC = 180 degrees
in equilateral triangle all sides are equal and hence all angles are equal. Hence AB=BC=AC ( from 1)
so ,
3AB=180 degrees (as AB=BC=CA)
AB=180/3 degrees
so, Angle AB = 60 degrees
Hence proofed
angle AB = Angle BC = Angle AC = 60 degrees
angle AB + Angle BC + Angle AC = 180 degrees
in equilateral triangle all sides are equal and hence all angles are equal. Hence AB=BC=AC ( from 1)
so ,
3AB=180 degrees (as AB=BC=CA)
AB=180/3 degrees
so, Angle AB = 60 degrees
Hence proofed
angle AB = Angle BC = Angle AC = 60 degrees
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