Show that the angles of an equilateral triangle are 60° each.
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Let the angles be x, y and z
Now by angle sum property
x + y + z = 180
Since, all the angles in equilateral triangle are equal so
x = y = z
Put x in place of y and z.
x + x + x = 180
3x = 180
x = 180 / 3
x = 60
Since x = y = z
So, x = 60, y = 60, z = 60
Hence proved
Regards
Now by angle sum property
x + y + z = 180
Since, all the angles in equilateral triangle are equal so
x = y = z
Put x in place of y and z.
x + x + x = 180
3x = 180
x = 180 / 3
x = 60
Since x = y = z
So, x = 60, y = 60, z = 60
Hence proved
Regards
mbchaithanya337:
thanks
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2
Hello mate ^_^
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Solution:
∆ABC is equilateral which means that
AB=BC=AC.
AB=AC means that ∠B=∠C (In triangle, angles opposite to equal sides are equal) .....(1)
AB=BC means that ∠A=∠C (In triangle, angles opposite to equal sides are equal) ...... (2)
From (1) and (2), we can say that
∠A=∠B=∠C .........(3)
Also, ∠A+∠B+∠C=180° (Angle sum property of triangle)
Putting (3) in the above equation, we get
∠A+∠A+∠A=180°
⇒3∠A=180°
⇒∠A=180/3=60° .......(4)
From (3) and (4), we can say that
∠A=∠B=∠C=60°
hope, this will help you.
Thank you______❤
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