Question

Show that the circumference of the Bohr orbit for the hydrogen atom is an integral multiple of the de Broglie wavelength associated with the electron revolving around the orbit.

Answer 1

For the angular momentum of an electron = mvr = nh/2π  (Say  1)

according to de Broglie equation λ = h/mv

And

mv = h/v (Say 2)

Placing 2 in 1

h/v =nh/2π or 2λr= nλ

Considering ‘2πr’ draws the circumference of the Bohr orbit (r), it is determined by equation (3) that the circuit of the Bohr orbit of the hydrogen atom is an indispensable multiple of de Broglie’s wavelength compared with electrons revolving around the orbit."

Answer 2

Answer:Solution is in the attachment....

Explanation: