Math, asked by iamabhaymittal6432, 1 year ago

Show that the cube of any integer is of the form 9k , 9k+1 , 9k-1

Answers

Answered by letshelpothers9

5

Step-by-step explanation:

Any number can be written as one of 3k−1, 3k or 3k+1 for some k. It's obvious what happens in the 3k case. Otherwise,

(3k±1)3=27k3±3⋅9k2+3⋅3k±1≡±1(mod9).

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