Question

show that the cube of any positive integer is of the form 4m, 4m+1 ,4m + 3 for some integer m.

Answer 1

$\bold{Answer:-}$


$\bold{Step\: by \:step \:explanation}$



Using

$(a + b) {}^{3} = a {}^{3} + b {}^{3} + 3ab {}^{2} + 3a {}^{2} b$




⏩⏩Refer to the attachment above for your solution ⬆ ⬆






Hope it helps!

Answer 2

$\mathbb{\red{\huge{Hey\:Lokesh}}}[\tex]</p><p></p><p></p><p></p><p>[tex]\textbf{Refer\:the\:above\:mentioned\:attachment}$