Question

show that the diagonal of a square are equal and bisect each other at right angle​

Answer 1

Answer:

they r equal

Step-by-step explanation:

this the solution

Answer 2

Step-by-step explanation:

let there be a square ABCD whose diagonal AC and BD intersect each other at a point O. Therefore, AO=OC and BO=OD.

Consider ∆s AOB and AOD in order to prove that the diagonals AC and BD are perpendicular to each other.

In ∆AOB and AOD

BO=OD. (O is mid-point)

OA=OA. (common side)

ABOUT=AD. (sides of a square are equal)

So, ∆AOB is congruent ∆AOD. (By SSS congruence condition)

= ang.AOB=ang.AOD

But, ang.AOB+ang.AOD=180°. (linear pair)

so, ang.AOB=ang.AOD=90°

Hence,the diagonals of a square bisect each other at right angles.