Question

show that the diagonal of a square are equal and bisect each other at a right angle triangle​

Answer 1

Answer:

Let the diagonals AC and BD intersect each other at a point O. To prove that the diagonals of a square are equal and bisect each other at right angles, we have to prove AC = BD, OA = OC, OB = OD, and AOB = 90º. Hence, the diagonals of a square are equal in length. Hence, the diagonals of a square bisect each other.

Answer 2

Answer:

let the square be ABCD,

< cad = <dab ( alternate )

<bad = <cad ( alternate)

so, by this, we can say diagonal of square is equal ..

now ,

as each angle of square is 90°

than,

diagonal are equal so each bisector equal to 45