show that the diagonal of a square are equal and bisect each other at a right angle triangle
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Let the diagonals AC and BD intersect each other at a point O. To prove that the diagonals of a square are equal and bisect each other at right angles, we have to prove AC = BD, OA = OC, OB = OD, and AOB = 90º. Hence, the diagonals of a square are equal in length. Hence, the diagonals of a square bisect each other.
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let the square be ABCD,
< cad = <dab ( alternate )
<bad = <cad ( alternate)
so, by this, we can say diagonal of square is equal ..
now ,
as each angle of square is 90°
than,
diagonal are equal so each bisector equal to 45
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