If the vertices of a triangle are (1,2),(4,-6)and(3,5) then find the area of triangle.
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please mark as brainlist answer
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Area of the triangle =
1/2 {x1(y2-y3) + x2(y3-y1) + x3(y1-y2)}
= 1/2 {1(-6-5) + 4(5-2) + 3(2-(-6))}
= 1/2 {1(-11) + 4(3) + 3(8)}
= 1/2 {-11+12+24}
= 1/2 (25)
= 25/2
=> 25/2 sq units
I hope this helps u..........
if yes then plz mark this as brainliest .
1/2 {x1(y2-y3) + x2(y3-y1) + x3(y1-y2)}
= 1/2 {1(-6-5) + 4(5-2) + 3(2-(-6))}
= 1/2 {1(-11) + 4(3) + 3(8)}
= 1/2 {-11+12+24}
= 1/2 (25)
= 25/2
=> 25/2 sq units
I hope this helps u..........
if yes then plz mark this as brainliest .
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