Question

Show that the diagonals of a rhombus divide it into four congruent triangles

Answer 1

Answer:

♣️Refer To Attachment♣️

Answer 2

Answer:

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Step-by-step explanation:

Let the rhombus be ABCD and let there diameters intersect each other at O.

Since,in a Rhombus all sides are equal,

Therefore AB=AD

and since ABCD is rhombus therefore its diagonals bisect each other

So,AO=DO

and

AO=AO(common)

Therefore 

ΔABO=~ΔADO

Similarly,ΔABO=~ΔBCO

Similarly,

ΔBCO=~ΔDCO

Therefore 

ΔABO=~ΔBCO=~ΔCDO=~ΔADO