Question

show that the difference of a two digit number and the number obtained by reversing digits is a multiple of 9​

Answer 1

Step-by-step explanation:

Let the two digit no. be XY ie., 10x+y

and it's reverse be yx i.e,10y+x

Their difference=10x+y-(10y+x)

=10x+y-10y-x

=9x-9y

=9(x-y)

Therefore their difference is a multiple of 9

H.p