Question

Show that the distance between (-1,3), (4, - 2) is 5√2 units.​

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

The distance between (-1, 3), (4, - 2) is 5√2 units, proved.

Step-by-step explanation:

Here, $x_{1} =-1,y_{1} =3$ and $x_{2} =4,y_{2} =-2$

Show that, the distance between (-1, 3), (4, - 2) is 5√2 units.

We know that,

The distance formula,

$\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

The distance between (-1, 3), (4, - 2)

= $\sqrt{(4-(-1))^{2}+(-2-3)^{2}}$

= $\sqrt{(4+1))^{2}+(-5)^{2}}$

= $\sqrt{5^{2}+(-5)^{2}}$

$= \sqrt{25+25}$

$= \sqrt{50}$

$= \sqrt{5\times 5\times 2}$

= 5$\sqrt{2}$ units, proved.

Thus, the distance between (-1, 3), (4, - 2) is 5√2 units,proved.