Question

show that the equation 2(m ^ 2 + n ^ 2) * x ^ 2 + 2(m + n) * x + 1 = 0 has no real roots, then "m" is not equal to ''n

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Answer 1

Answer:

this question is very tough

Answer 2

Answer:

2(m

2

+n

2

)x

2

+2(m+n)+1=0

D=B

2

−4AC

D=[2(m+n)]

2

−4×2(m

2

+n

2

)

After solving you will get D=−4(m−n)

2

As (m−n)

2

is always positive

Hence, D<0

Step-by-step explanation:

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