Question

Show that the equation 2x^2-5x-4=0 has real and unequal roots

Answer 1

Answer:

Step-by-step explanation:

Answer 2

$2x ^{2} - 5x - 4 = 0$

To find the nature of roots,

Discriminate must be greater that zero. Check that,

${b}^{2} - 4ac = 25 + 32$

That is greater than 0.

Thus, the given equation has real and distinct roots.