Show that the equation ax+ by+ 6= 0, by+ cz+ p= 0,cz+ax+q=0 represent plane representing perpendicular to xy,yz,zx planes
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i, j , k are unit vectors in x, y, z directions.
PL1: a x + b y + 6 = 0, Normal N1: a i + b j is in the x-y plane. So PL1 is perpendicular to the x-y plane.
PL2: b y + c z + p = 0, Normal N2: b j + c k is in the y-z plane. So PL2 is perpendicular to y-z plane.
PL3: c z + a x + q = 0, Normal N3: c k + a i is in the z-x plane. So PL3 is perpendicular to z-x plane.
PL1: a x + b y + 6 = 0, Normal N1: a i + b j is in the x-y plane. So PL1 is perpendicular to the x-y plane.
PL2: b y + c z + p = 0, Normal N2: b j + c k is in the y-z plane. So PL2 is perpendicular to y-z plane.
PL3: c z + a x + q = 0, Normal N3: c k + a i is in the z-x plane. So PL3 is perpendicular to z-x plane.
kvnmurty:
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