show that the equation of normal at any point on the curve x=3 cos a - cos3 a , y= 3 sin a - sin3a is 4(y cos3a - x sin3a)=3 sin(4a)?
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Sin^2A+cos^2A=1. So given condition can be revised as (Sin A-cosA) (sin^2A+ cos^2A-sin A cos A).
Do the items. Answer will come. Be that as it may, I think there is some mix-up. Either first section term has + or second one positive. Both can't be negative.
The other term in the brackets, being second degree in wrongdoing An and cos A, recommends that that may be helpful.
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