show that the equation has no real roots
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Answer:
b^2-4ac <0 (No real roots imaginary roots)
Step-by-step explanation:
b^2-4ac <0 (No real roots imaginary roots)
a = 2
b= -3
c= 4
(-3)^2 - (4*2*4)
9-32
-23
Since b^2-4ac <0 (-23<0) It is not
real roots imaginary roots
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