Show that the escope velocity is given by √gr
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Answer:
Escape Velocity is √2 times of orbital Velocity.
Proof:
Orbital velocity of satellites is given as :
\begin{gathered}orbital \: v = \sqrt{ \frac{Gm}{r} } \\ \end{gathered}
orbitalv=
r
Gm
Where m => mass of Earth , r => radius of Earth.
Escape Velocity can be calculated by the us of Conservation of Energy theorem:
KE1 + PE1 = KE2 + PE2
\frac{1}{2} M{(v. \: esc)}^{2} - \frac{GmM}{ {r}^{2} } = 0 + 0
2
1
M(v.esc)
2
−
r
2
GmM
=0+0
\begin{gathered} = > v \: esc. = \sqrt{ \frac{2Gm}{r} } \\ \end{gathered}
=>vesc.=
r
2Gm
\begin{gathered} = > v \: esc. = \sqrt{2 } \times ( \sqrt{ \frac{Gm}{r} } ) \\ \end{gathered}
=>vesc.=
2
×(
r
Gm
)
= > v \: esc. = \sqrt{2} \times (orbital \: v)=>vesc.=
2
×(orbitalv)
[Hence proved.
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