Show that the following numbers are irrational
(i)
(ii)
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(i) SOLUTION :
Let us assume , to the contrary ,that 1/√2 is rational. Then,it will be of the form a/b where a, b are co primes integers and b ≠0.
1/√2 = a/b
1 × √2 /√2×√2 = a/b
[On rationalising the denominator]
√2/2 = a/b
√2 = 2a/b
since, a & b is an integer so,2a/b is a rational number.
∴ √2 is rational
But this contradicts the fact that √2 is an irrational number .
Hence, 1/√2 is an irrational .
(ii) SOLUTION :
Let us assume , to the contrary ,that 7√5 is rational. Then,it will be of the form a/b where a, b are co primes integers and b ≠0.
7√5 = a/b
√5 = a/7b
since, a & 7b is an integer so, a/7b is a rational number.
∴ √5 is rational
But this contradicts the fact that √5 is an irrational number .
Hence, 7√5 is irrational .
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