Show that the following points form a equilateral
triangle A(a,0), B(-a, 0), C(0, a √13)
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Answer:
give a(a,0),B(-a,0),C(0,a√3).
AB=√(a-(a))2+(0-0)2= √4a2=2a
BC=√(0-(-a))2+(a√3)2=√4a2=2a
CA=√(0-(-a))2+(a√3)2=√4a2=2a
Step-by-step explanation:
.°.AB=BC=CA
Hence,it is an equilateral triangle,
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