The distance between two stations is 230 km.Two scooterist start simultaneously towards each other one from a and another from b if the speed of one scooterist is 10 km less than that of the other then find the speed of each scooterist if the distance between them after 3 hours of their start is 20 km.
Answers
Answered by
1
Answer:
Speed of first cyclist = X km/hr
speed of other cyclist = (X - 10) km/hr
distance covered by first cyclist
after 3 hours = 3X km
distance covered by other cyclist
after 3 hours = 3(X - 10) km
= (3X - 30) km
according to condition,
3X + 3X - 30 + 20 = 230
6X -10 = 230
6X = 230 + 10
6X = 240
X = 240/6
X = 40
therefore,
speed of first cyclist = X
= 40 km
speed of other cyclist = X - 10
= 40 - 10
= 30 km
Step-by-step explanation:
Hiiiii Harshita!!!!!!!!!!
Similar questions