show that the following points from a equilateral triangle A(a,0),B(-a,0),C(0,a√3)
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Step-by-step explanation:
AB = √(-a-a)^2+(0-0)^2= 2a
BC = √(0+a) ^2+(a√3-0) ^2=√a^2+3a^2=√4a^2=2a
CA = √(0-a) ^2+(a√3-0) ^2=√a^2+3a^2=√4a^2=2a
AB = BC = CA = 2a
show triangle ABC is an equilateral triangle
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