Question

show that the following points taken in order form an equilateral triangle in each case
(i) A(2,2),B(-2,-2),C(-2√3,2√3)stepsfor this question
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Answer 1

Answer:

(i) A(2,2) , B(-2,-2) and C= (-2√3,2√3)

use distance formula,

length of AB = √{(-2-2)² + (-2-2)²} = 4√2 unit

length of BC = √{(-2+2√3²+(-2-2√3)²}

= √{2(2² + 2²√3²)} unit

= √{2(4 + 12)} = 4√2 unit

length of CA = √{(2+2√3)²+(2-2√3)²}

= √2(4 + 12) = 4√2 unit

here, AB = BC = CA

then, ABC is an equilateral triangle.

Answer 2

Answer:

Step-by-step explanation:

hope it helpes u