Physics, asked by indrajeetsingh1606, 1 year ago

show that the gravitational field intensity of the earth at any point is equal to the acceleration produced in the freely falling body at that point ​

Answers

Answered by PVSRam
0

Answer:

center of gravity is the answer. if it is correct treat it as brainlist answer.

Answered by HrishikeshSangha
5

The gravitational field strenght at a point E=F/m

  • Acceleration produced in a freely  falling body due to gravity is a=F/m
  • Combining both the formula we get E=a
  • Which means Gravitational force strength at a place is equal to the acceleration produced in a freely falling body at that point.
  • There is also factor that if the earth r increases and the gravitational potential decreases but negative sign shows Vg increases with increase of r.
  • Vg= -GM/r
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