Physics, asked by indrajeetsingh1606, 11 months ago

show that the gravitational field intensity of the earth at any point is equal to the acceleration produced in the freely falling body at that point ​

Answers

Answered by PVSRam
0

Answer:

center of gravity is the answer. if it is correct treat it as brainlist answer.

Answered by HrishikeshSangha
5

The gravitational field strenght at a point E=F/m

  • Acceleration produced in a freely  falling body due to gravity is a=F/m
  • Combining both the formula we get E=a
  • Which means Gravitational force strength at a place is equal to the acceleration produced in a freely falling body at that point.
  • There is also factor that if the earth r increases and the gravitational potential decreases but negative sign shows Vg increases with increase of r.
  • Vg= -GM/r
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