show that the line x - y - z + 3 = 0 = 3x + 3y - z - 15 is normal to the plane 2x - y + 3z + 4 = 0
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Steps and Understanding :
1) Direction Ratio of line will be perpendicular to normal vector of two given planes.
We will find it by cross product of normal vector of given planes.
2) Then, we will observe that direction ratio of line is multiple of normal vector of 2x-y+3z+4=0
Hence, Given line is multiple of 2x-y+3z+4=0 .
1) Direction Ratio of line will be perpendicular to normal vector of two given planes.
We will find it by cross product of normal vector of given planes.
2) Then, we will observe that direction ratio of line is multiple of normal vector of 2x-y+3z+4=0
Hence, Given line is multiple of 2x-y+3z+4=0 .
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