show that the numbers 8 ki power n can never end with digit 0 for any natural number n
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If any digit had last digit 10 that means that it is divisible by 10 and the factors of 10 are 2 and 5.
So the value 8^n should be divisible by 2 and 5 both.
8 ^n is divisible by 2 but not divisible by 5. So it cannot end with 0.
So the value 8^n should be divisible by 2 and 5 both.
8 ^n is divisible by 2 but not divisible by 5. So it cannot end with 0.
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