show that the p square will leave a remainder 1 when divided by 8 if P is an odd positive integer
Answers
Answered by
4
Your question is solved plz mark as brainliest
Attachments:
Answered by
6
if p is an odd interger it can be written as 4q+1
p=4q+1
square both sides
p^2= 16q^2 + 8q +1
p^2= 8(2q^2+q) +1
so it leaves remainder 1
p=4q+1
square both sides
p^2= 16q^2 + 8q +1
p^2= 8(2q^2+q) +1
so it leaves remainder 1
Similar questions