show that the point (11,-2) is equidistant from the points (4,-3) and (6,3)
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so let A (11,-2)
B (4,-3)
C(6,3)
using distance formula
AB = √{(11-4)² + (-2+3)²} = √50 unit
AC = √{(11-6)² + (-2-3)²} = √50 unit
So hence we see AB = AC proved
B (4,-3)
C(6,3)
using distance formula
AB = √{(11-4)² + (-2+3)²} = √50 unit
AC = √{(11-6)² + (-2-3)²} = √50 unit
So hence we see AB = AC proved
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thank u vry much
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