show that the point A (1 - 2)b (3,6) C(5,10) and D(3,2)are the vertices of a parallelogram
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You plot on the graph paper then if u see parallelogram they are the vertices....
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slope of line AB =6-(-2)/3-1 = 8/2 = 4
slope of line CD =2-10/3-5 = -8/-2 = 4
hence, ABIICD , Similarly prove ADIIBC
since ABIICD & ADIIBC
hence given vertices are of a parallelogram
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