Question

Show that the point are co-linear A(6,9)B(0,1)C(-6,-7)

Answer 1

HEYA!!
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If points are collinear, then area of triangle =0

$\frac{1}{2} (x1(y2 - y3) + x2(y3 - y2) + x3(y2 - y1) \\ \\ = > \frac{1}{2} (6(8) + 0( - 7 - 9) + - 6(1 - 9)) \\ \\ = > \frac{1}{2} (48 + 0 - 48) = 0 \\ \\ (48 - 48) = 0$
Hence area of triangle =0

Therefore the points are collinear..

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