Show that the points (0,0) , (3a, √3a) and (3a, -√3a) are the vertices of an equilateral triangle
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Step-by-step explanation:
A(0,0), B(3a, √3a), C(3a, √3a)
AB = √[(3a)²+(√3a)²] = √(9a²+3a²) = 2a√3
BC = √[(3a-3a)²+(√3a-(-√3a))²] = 2a√3
AC = √[(3a)²+(-√3a)²] = √(9a²+3a²) = 2a√3
AB = AC = BC ===> Δ ABC is equilateral triangle.
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