Show that the points (1, 1), (4, 4) and
(6, 2) are the vertices of a right angled triangle.
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Answer:
AB=√(x²-x¹)²+(y²-y¹)²
AB=(4-1)²+(4-1)²
AB=√(3²+3²)
AB=√(9+9)
AB=√18
AB=3√2units
BC=√(x²-x¹)²+(y²-y¹)²
BC=√(6-4)²+(2-4)²
BC=√(2²)+(-2²)
BC=√4+4
BC=√8
BC=2√2 units
AC=√(6-1)²+(2-1)²
AC=√(5²+1²)
AC=√(25+1)
AC=√26
AC=√26units
AB²+BC²=AC²
(3√2)²+(2√2)²=(√26)²
18+8=26
26=26
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