Question

Show that the points (1,-1) ,b (2,6) and c(0-8) lie on the graph of the linear equation 7x-y=8

Answer 1

Step-by-step explanation:

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Answer 2

The proof is given below:

Given points

A (1, -1)

B (2, 6)

C (0, -8)

If we find the equation of the line passing through A and C

$(y-y_1)=\frac{y_2-y_1}{x_2-x_1}(x_2-x_1)$

$(y-(-8))=\frac{-1+8}{1-0}(x-0)$

or $y+8=7x$

or, $7x-y=8$

Which is the equation of given line

Therefore, points A and C lie on the line

Putting the coordinates of B on this line

LHS = 7 × 2 - 6 = 14 - 6 = 8 = RHS

Therefore, the point B also lies on this line.

Hope this answer is helpful.

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