Show that the points (14,10),(11,13)and (2,-2) are the vertices of a right angle triangle tell this solution
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let A(14,10), B(11,13), C(2,-2)
AB^2=(14-11)^2+(10-13)^2
AB^2= 9+9=18
BC^2=(11-2)^2+(13+2)^2
BC^2=81+225=306
CA^2=(14-2)^2+(10+2)^2
CA^2=144+144=288
AB^2+CA^2=BC^2
PROVED
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