show that the points (-2,-3),(1,0),(4,3)and (1,2)taken in order are the vertices of a parallelogram
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Step-by-step explanation:
We have the points
P(−2,−1),Q(1,0),R(4,3) and S(1,2)
We know the property the of parallelogram that diagonals of parallelogram bisect each other.
Let us find out mid-point of line joining P and R and line joining Q and S
(i) Mid-point M of diagonal PR
M(
2
−2+4
,
2
−1+3
)
⇒M(1,1)
(ii) Mid-point M
′
of diagonal QS
M
′
(
2
1+1
,
2
0+2
)
⇒M
′
(1,1)
From (i) & (ii)
Mid-points M & M
′
are identical
⇒ Diagonals of the figure PQRS bisect each other and this property is enough to prove that it is a parallelogram.
Although we can also check by distance formula i.e. d=
(a−c)
2
+(b−d)
2
PQ=RS
SP=QR
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