show that the points (a,0), (0,b) and (3a,-2b) are collinear. Also find the equation of the line containing them
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Answer:
Step-by-step explanation:
Equation of line passing through (a,0) and (0,b) is x/a+y/b=1
Now we have to check whether the point (3a,-2b) lies on it
Putting x=3a and y=-2b in the above equation,
3a/a+(-2b/b)=3-2=1
So the point (3a,-2b) lies on the line.
So the points are collinear.
Hope you got it.
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