Question

Show that the points (a,0), (2a, -b) and (-a, 2b) are collinear.​

Answer 1

Answer:

let the points be P (a,0), Q (2a, -b), R (-a, 2b)

PQ = √(2a-a)^2 + (-b-0)^2 = √(a^2 + b^2)

QR =√(3a)^2+ (3b)^2 = 3√(a^2 + b^2

PR = √(2a)^2 + (2b)^2 = 2 √(a^2 + b^2)

You can see that

PQ + PR = QR

Therefore points P,Q,R are collinear