Show that the points A (4,7),B(8,4) and C(7,11) are the vertices of a right angle triangle?
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Answer:
Let the points be A, B and C respectively..
by distance formula
AB=√[(8-4)²+(4-7)²]
= 5 units
similarly,
BC= 5√2 units
AC= 5 units
AC²+BC²= 25+50
=75
and AB²=25
therefore A, B, C form a right angled triangle
forming a right angle at C
(inverse of Pythagoras theorem)
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