show that the points A (5,0),B (11,0) and C (8,4) are the vertices of an isosceles triangle
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Given points ,
A(5,0) , B(11,0) & C(8,4)
the distance between A and B =√(x2-x1)^2 + (y2-y1)^2
√(11-5)^2 + (0-0)^2
√6^2 =6
therefore , the distance between A and B = 6 units
similarly ,
the distance between B and C = 5 units
the distance between C and A = 5 units
from the above ,
CA = BC ≠AB
hence , the given points are the vertices of a isosceles triangle
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