show that the product of any three consecutive even integers is divisible by 48
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Answered by
4
let the integers be 2,4,6.
then their product is 48 which is completely divisible by 48.
Hope this works :)
then their product is 48 which is completely divisible by 48.
Hope this works :)
rishie:
hey
Answered by
10
The product of any three consecutive even integers is divisible by 48.
Step-by-step explanation:
Let the three consecutive even integers = x, (x + 2) and (x + 4)
To prove that, the product of any three consecutive even integers is divisible by 48.
According to question,
x(x + 2)(x + 4) is divisible by 48.
Put x = 2, 4, 6, 8, 10, ......
Put x = 2, we get
2(2 + 2)(2 + 4)
=2(4)(6) =48, is divisible by 48
Put x = 4, we get
4(4 + 2)(4 + 4)
=4(6)(8) =192, is divisible by 48
...
Hence, the product of three consecutive even integers is divisible by 48.
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