show that the progression 4, 7, 10, 13, .... is an AP. find its general term.
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Its general term is 3n + 1.
The given Arithmetic Progression (A.P.) is 4,7,10,13,...
Let us find out the difference between two consecutive terms.
7-4 = 3
10-7 = 3
13-10 3
Since the common difference (d) between the two consecutive numbers are same, we can say that the progression is an AP.
Let the general term be an.
The nth term is given as :
an = a + (n-1)d
where, a is the first term, a = 4 and d = 3
So,
an = 4 + 3(n-1)
= 4 + 3n - 3
= 3n + 1
This is the general term.
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