show that the quardilateral formed by joining the midpoint of the consecutive sides of square is also a square
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Step-by-step explanation:
Let ABCD is a square.
AB = BC = CD = AD P,Q,R and S are mid-points of AB,BC,CD and DA, respectively.
Now, in ΔADC, SR||AC and SR = 1/2 AC In ΔABC,
PQ||AC and PQ = 1/2 AC SR||PQ and SR = PQ = 1/2 AC
Similarly, SP||BD and BD||RQ SP||RQ and SP = 1/2 BD And RQ = 1/2 BD SP = RQ = 1/2 BD
Since, diagonals of a square bisect each other at right angles.
AC = BD SP = RQ = 1/2 AC SR = PQ = SP = RQ All sides are equal. Now, in quad OERF, OE||FR and OF||ER ∠EOF = ∠ERF = 90
Hence, PQRS is a square
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