Question

Show that the rate of change of
momentum
massx acceleration.
under what Condition does this
relation
hold 2​

Answer 1

Explanation:

inital velocity =u

final velocity =v

time taken = t

intial momentum = mass * intial velocity = m*u=mu

final momentum = Mass* final velocity = m *v= mv

rate of change of momentum = mv-mu/t

so ,

force = rate of change of momentum

F = mv-mu/t

F= m( v-u)/t

F= m*a ( as acceraleration = v-u/t)

F=ma

according to second law of motion ,force is directly proportional to m*a

so, F is directly proportional to ma

F=k*ma (k = constant)

take F=1N ; mass = 1 kg ; acceralation = 1m/s ^2

F= k*ma

1 = k* 1 *1

1=k*1

1/1=k

1= k