Question

Show that the rate of first order reaction is doubled when concentration of the reactant is doubled

Answer 1

r=k[A] for 1st order reaction

new rate, r'=k[2A]=2k[A]=2r

PLS MARK MY ANSWER AS BRAINLIEST..

Answer 2

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$Rate=k[A]^x$  

For first order reaction, x= 1

$Rate'=k[2A]^1$  

$Rate=k[2]^1[A]^1$  

$Rate=2\times Rate$  

Thus rate of first order reaction is doubled when concentration of the reactant is doubled

Learn more about first order kinetics

https://brainly.in/question/3143885

https://brainly.com/question/13301088