Show that the ratio of equation (b-c)x²+(c-a)x+(a-b) are rational
Answers
Answered by
0
Answer:
Sorry but I don't know
Step-by-step explanation:
Sorry
S
Answered by
3
If the roots of the equation (b-c)x*2+(c-a)x+(a-b)=0are equal then.Prove that 2b=a+cyour answer is here...(b-c)x²+(c-a)x+(a-b)=0Comparing with quadratic equationAx²+Bx+C=0A=(b-c),B=c-a,C=a-bDiscriminate when roots are equalD=B²-4AC=0D=(c-a)²−4(b-c)(a-b)=0D=(c²+a²−2ac)-4(ba-ac-b²+bc)=0D=c²+a²−2ac-4ab+4ac+4b²-4bc=0c²+a²+2ac-4b(a+c)+4b²=0(a+c)²-4b(a+c)+4b²=0[(a+c)-2b]²=0a+c=2b
Similar questions