Show that the ratio of the amplitudes of the conduction current density and
displacement current density is
σ /w
for the applied field amplitude ratio if
the applied field is E= Eme-t/T where T is real.
Answers
Answer:
good luck to the team you support and 6ARead the following and answer any four questions:
The following is the diagram of an electric motor:
a) Which part of the electric motor in the above figure) can be used as an armature after
some modifications?
(1) POXY
(n) YXOP
(I) ABCD
(iv) ABPQ
Page (4)
b) What are these modifications in the part mentioned above?
1) large number of turns
il) s soft iron core
(1) both large number of turns and a soft iron core
(iv) none of these
Which part in the above diagram is replaced by an electromagnet in order to make a
Commercial motor?
(1) X and Y
(ii) Pando
(im) R
(iv) None of these
ehich part in the above diagram is a device that reverses the direction of flow of
current through a circuit?
1) X and Y
(11) P and Q
(117) R
(iv) None of these
Which part in the above diagramis used as an axle in the electric motor?
6) X and Y
(11) P and q
(in) R
(iv) None of theseM will make a difference
Answer:
given: E=Em exp(-t/T)
Jc= (sigma) E
Jc=(sigma) Em exp(-t/T)
Jd=(Epsilon) dE/dt
Jd=(epsilon) Em(-1/T) exp(-t/T)
|Jc|/|Jd|=(sigma) Em exp(-t/T) / (epsilon) (Em/T) exp(-t/T)
|Jc|/|Jd|=(sigma) T/ (epsilon)