Question

show that the real show that the polynomial given below have no real number X square + 6 X + 10​

Answer 1

$\huge \mathtt{ \fbox{Solution :)}}$

Given ,

The polynomial is (x)² + 6x +10

Here ,

• b = 6
• a = 1
• c = 10

We know that , discriminate of quadratic equation is given by

$\large \mathtt{ \fbox{Discriminate = {(b)}^{2} - 4ac}}$

Thus ,

D = (6)² - 4(1)(10)

D = 36 - 40

D = - 4 < 0

Hence , the equation has no real roots

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